What is (3/4+7/8)/(2/5-8/9) ?

The solution to (3/4+7/8)/(2/5-8/9) is -585/176

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simplify (3/4+7/8)/(2/5-8/9)

simplify

\frac{\frac{3}{4} + \frac{7}{8}}{\frac{2}{5} - \frac{8}{9}}

- \frac{585}{176}

Decimal Notation

- 3.32386 \dots

Solution steps

\frac{\frac{3}{4} + \frac{7}{8}}{\frac{2}{5} - \frac{8}{9}}

\frac{3}{4} + \frac{7}{8} = \frac{13}{8}

= \frac{\frac{13}{8}}{\frac{2}{5} - \frac{8}{9}}

\frac{2}{5} - \frac{8}{9} = - \frac{22}{45}

= \frac{\frac{13}{8}}{- \frac{22}{45}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{13}{8}}{\frac{22}{45}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{13}{8}}{\frac{22}{45}} = \frac{13 \cdot 45}{8 \cdot 22}

= - \frac{13 \cdot 45}{8 \cdot 22}

Multiply the numbers:

13 \cdot 45 = 585

= - \frac{585}{8 \cdot 22}

Multiply the numbers:

8 \cdot 22 = 176

= - \frac{585}{176}

524 + 23 + 46

\frac{sec ^{2} ( θ ) - 1}{sec ^{2} ( θ )}

\frac{2 x ^{\frac{3}{2}}}{( 16 x ^{4} ) ^{\frac{1}{4}}}

\frac{3}{2 x - 2} + \frac{x + 1}{4}

\frac{18}{16}