What is ((2-i)(4-3i)^2)/(3+2i) ?

The solution to ((2-i)(4-3i)^2)/(3+2i) is -140/13-145/13 i

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simplify ((2-i)(4-3i)^2)/(3+2i)

simplify

\frac{( 2 - i ) ( 4 - 3 i ) ^{2}}{3 + 2 i}

- \frac{140}{13} - \frac{145}{13} i

Solution steps

\frac{( 2 - i ) ( 4 - 3 i ) ^{2}}{3 + 2 i}

Multiply by the conjugate

\frac{3 - 2 i}{3 - 2 i}

= \frac{( 2 - i ) ( 4 - 3 i ) ^{2} ( 3 - 2 i )}{( 3 + 2 i ) ( 3 - 2 i )}

Simplify

\frac{( 2 - i ) ( 4 - 3 i ) ^{2} ( 3 - 2 i )}{( 3 + 2 i ) ( 3 - 2 i )} : \frac{- 145 i - 140}{13}

= \frac{- 145 i - 140}{13}

Rewrite in standard complex form:

- \frac{140}{13} - \frac{145}{13} i

= - \frac{140}{13} - \frac{145}{13} i

\frac{4}{3 x ^{3}} + \frac{x}{6 x ^{3} + 3 x ^{2}}

(x^{3} - 2 x + 3) + (3 x^{2} + 6 x - 2)

\frac{8 x ^{3} - 27}{2 x - 3}

6.022 \cdot 1 0^{23}

(x - 2)^{3} + 1

What is ((2-i)(4-3i)^2)/(3+2i) ?
The solution to ((2-i)(4-3i)^2)/(3+2i) is -140/13-145/13 i