What is (x^3-2x+3)+(3x^2+6x-2) ?

The solution to (x^3-2x+3)+(3x^2+6x-2) is x^3+3x^2+4x+1

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simplify (x^3-2x+3)+(3x^2+6x-2)

simplify

(x^{3} - 2 x + 3) + (3 x^{2} + 6 x - 2)

x^{3} + 3 x^{2} + 4 x + 1

Solution steps

(x^{3} - 2 x + 3) + (3 x^{2} + 6 x - 2)

Simplify

(x^{3} - 2 x + 3) + (3 x^{2} + 6 x - 2) : x^{3} - 2 x + 3 + 3 x^{2} + 6 x - 2

= x^{3} - 2 x + 3 + 3 x^{2} + 6 x - 2

Group like terms

= x^{3} + 3 x^{2} - 2 x + 6 x + 3 - 2

Add similar elements:

- 2 x + 6 x = 4 x

= x^{3} + 3 x^{2} + 4 x + 3 - 2

Subtract the numbers:

3 - 2 = 1

= x^{3} + 3 x^{2} + 4 x + 1

\frac{8 x ^{3} - 27}{2 x - 3}

6.022 \cdot 1 0^{23}

(x - 2)^{3} + 1

\frac{4 m}{15 m ^{2} n} - \frac{8 n}{10 m n ^{3}}

18 \frac{x}{9}

What is (x^3-2x+3)+(3x^2+6x-2) ?
The solution to (x^3-2x+3)+(3x^2+6x-2) is x^3+3x^2+4x+1