What is (x^3+2x^2-9x-18)/(x^3-x^2-6x) ?

The solution to (x^3+2x^2-9x-18)/(x^3-x^2-6x) is (x+3)/x

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simplify (x^3+2x^2-9x-18)/(x^3-x^2-6x)

simplify

\frac{x ^{3} + 2 x ^{2} - 9 x - 18}{x ^{3} - x ^{2} - 6 x}

\frac{x + 3}{x}

Solution steps

\frac{x ^{3} + 2 x ^{2} - 9 x - 18}{x ^{3} - x ^{2} - 6 x}

Factor

x^{3} + 2 x^{2} - 9 x - 18 : (x + 2) (x + 3) (x - 3)

= \frac{( x + 2 ) ( x + 3 ) ( x - 3 )}{x ^{3} - x ^{2} - 6 x}

Factor

x^{3} - x^{2} - 6 x : x (x + 2) (x - 3)

= \frac{( x + 2 ) ( x + 3 ) ( x - 3 )}{x ( x + 2 ) ( x - 3 )}

Cancel the common factor:

x + 2

= \frac{( x + 3 ) ( x - 3 )}{x ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x}

\frac{12}{32}

\frac{4}{5} \div \frac{3}{8}

\frac{cos ^{2} ( x ) + sin ^{2} ( x )}{cos ^{2} ( x )}

(x + 5)^{2} - (x + 4)^{2} - (x - 3)^{2} + (x - 4)^{2}

What is (x^3+2x^2-9x-18)/(x^3-x^2-6x) ?
The solution to (x^3+2x^2-9x-18)/(x^3-x^2-6x) is (x+3)/x