What is 8(sin(x)cos(x))^2+cos(4x) ?

The solution to 8(sin(x)cos(x))^2+cos(4x) is 8sin^2(x)cos^2(x)+cos(4x)

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simplify 8(sin(x)cos(x))^2+cos(4x)

simplify

8 (sin (x) cos (x))^{2} + cos (4 x)

8 sin^{2} (x) cos^{2} (x) + cos (4 x)

Solution steps

8 (sin (x) cos (x))^{2} + cos (4 x)

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(sin (x) cos (x))^{2} = sin^{2} (x) cos^{2} (x)

= 8 sin^{2} (x) cos^{2} (x) + cos (4 x)

1 6^{- 2^{- 1}}

2 \frac{8}{9} \cdot \frac{1}{2}

(- 2 + 2 i)^{3}

csc^{2} (θ) - 1

tan (x) \cdot cos (x)

What is 8(sin(x)cos(x))^2+cos(4x) ?
The solution to 8(sin(x)cos(x))^2+cos(4x) is 8sin^2(x)cos^2(x)+cos(4x)