What are the solutions to the equation 2x^2+80=26x ?

The solutions to the equation 2x^2+80=26x are x=8,x=5

Find the zeros of 2x^2+80=26x

The zeros of 2x^2+80=26x are x=8,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 80 = 26 x

x = 8, x = 5

Solution steps

2 x^{2} + 80 = 26 x

Move

26 x

to the left side

2 x^{2} + 80 - 26 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 26 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 2 \cdot 80}{2 \cdot 2}

(- 26)^{2} - 4 \cdot 2 \cdot 80 = 6

x_{1, 2} = \frac{- ( - 26 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 26 ) - 6}{2 \cdot 2}

x = \frac{- ( - 26 ) + 6}{2 \cdot 2} : 8

x = \frac{- ( - 26 ) - 6}{2 \cdot 2} : 5

The solutions to the quadratic equation are:

x = 8, x = 5

- 45 x - 45 = - 75 x + 75

- 23 + 5 (4 - x) \geq - 3 (x + 7)

r^{2} + 10 r + 26 = 0

x^{2} - 10 x y - 24 y^{2}

- 9 - - 4

What are the solutions to the equation 2x^2+80=26x ?
The solutions to the equation 2x^2+80=26x are x=8,x=5
Find the zeros of 2x^2+80=26x
The zeros of 2x^2+80=26x are x=8,x=5