What is (7a^2+5a+3)+(-3a^2+2a-4) ?

The solution to (7a^2+5a+3)+(-3a^2+2a-4) is 4a^2+7a-1

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simplify (7a^2+5a+3)+(-3a^2+2a-4)

simplify

(7 a^{2} + 5 a + 3) + (- 3 a^{2} + 2 a - 4)

4 a^{2} + 7 a - 1

Solution steps

(7 a^{2} + 5 a + 3) + (- 3 a^{2} + 2 a - 4)

Simplify

(7 a^{2} + 5 a + 3) + (- 3 a^{2} + 2 a - 4) : 7 a^{2} + 5 a + 3 - 3 a^{2} + 2 a - 4

= 7 a^{2} + 5 a + 3 - 3 a^{2} + 2 a - 4

Group like terms

= 7 a^{2} - 3 a^{2} + 5 a + 2 a + 3 - 4

Add similar elements:

7 a^{2} - 3 a^{2} = 4 a^{2}

= 4 a^{2} + 5 a + 2 a + 3 - 4

Add similar elements:

5 a + 2 a = 7 a

= 4 a^{2} + 7 a + 3 - 4

Subtract the numbers:

3 - 4 = - 1

= 4 a^{2} + 7 a - 1

(1 - cos (2 x)) (1 + cos (2 x))

\frac{cot ( θ )}{tan ( θ )}

49 - 42 a + 9 a^{2}

(4 a + 2 b)^{2}

2 x^{5} + 5 x^{4} + 11 x^{3} - 49 x^{2} - 31 x + 26

What is (7a^2+5a+3)+(-3a^2+2a-4) ?
The solution to (7a^2+5a+3)+(-3a^2+2a-4) is 4a^2+7a-1