What is factor 8x^6+7x^3-1 ?

The solution to factor 8x^6+7x^3-1 is (x+1)(x^2-x+1)(2x-1)(4x^2+2x+1)

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factor 8x^6+7x^3-1

factor

8 x^{6} + 7 x^{3} - 1

(x + 1) (x^{2} - x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

Solution steps

8 x^{6} + 7 x^{3} - 1

Use the rational root theorem

= (x + 1) \frac{8 x ^{6} + 7 x ^{3} - 1}{x + 1}

\frac{8 x ^{6} + 7 x ^{3} - 1}{x + 1} = 8 x^{5} - 8 x^{4} + 8 x^{3} - x^{2} + x - 1

= (x + 1) (8 x^{5} - 8 x^{4} + 8 x^{3} - x^{2} + x - 1)

Factor

8 x^{5} - 8 x^{4} + 8 x^{3} - x^{2} + x - 1 : (x^{2} - x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

= (x + 1) (x^{2} - x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

2^{2} = 4

= (x + 1) (x^{2} - x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

\frac{( x ^{- 2} y ^{4} ) ^{3}}{( x y ) ^{- 3}}

(5 + 24 + 5 - 24)^{2}

192 a^{36} b^{9}

\frac{p ^{2} + p}{2 p}

v^{2} - 10 v + 21

What is factor 8x^6+7x^3-1 ?
The solution to factor 8x^6+7x^3-1 is (x+1)(x^2-x+1)(2x-1)(4x^2+2x+1)