What is sqrt((4x^2)/(28y^4z^5)) ?

The solution to sqrt((4x^2)/(28y^4z^5)) is x/(sqrt(7)y^2z^2\sqrt{z)}

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simplify sqrt((4x^2)/(28y^4z^5))

simplify

\frac{4 x ^{2}}{28 y ^{4} z ^{5}}

\frac{x}{7 y ^{2} z ^{2} z}

Solution steps

\frac{4 x ^{2}}{28 y ^{4} z ^{5}}

Cancel

\frac{4 x ^{2}}{28 y ^{4} z ^{5}} : \frac{x ^{2}}{7 y ^{4} z ^{5}}

= \frac{x ^{2}}{7 y ^{4} z ^{5}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b},

assuming

a \geq 0, b \geq 0

= \frac{x ^{2}}{7 y ^{4} z ^{5}}

Apply radical rule:

a^{2} = a,

assuming

a \geq 0

x^{2} = x

= \frac{x}{7 y ^{4} z ^{5}}

Simplify

7 y^{4} z^{5} : 7 y^{2} z^{2} z

= \frac{x}{7 y ^{2} z ^{2} z}

\frac{x ^{2} - 16}{x - 2}

(a + b + c)^{2} - (a - b + c)^{2}

(10 x - y + 4) - [- (- 7 x - 21 + 3 y) - (- 3 (- 11 y + 9 x - 5))]

\frac{6 x ^{2}}{x - 1} + \frac{- 6 x}{x - 1}

What is sqrt((4x^2)/(28y^4z^5)) ?
The solution to sqrt((4x^2)/(28y^4z^5)) is x/(sqrt(7)y^2z^2\sqrt{z)}