What is (e^4)/(e^{-1)+e^{-2}} ?

The solution to (e^4)/(e^{-1)+e^{-2}} is (e^6)/(e+1)

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simplify (e^4)/(e^{-1)+e^{-2}}

simplify

\frac{e ^{4}}{e ^{- 1} + e ^{- 2}}

\frac{e ^{6}}{e + 1}

Decimal Notation

108.49871 \dots

Solution steps

\frac{e ^{4}}{e ^{- 1} + e ^{- 2}}

Simplify

e^{- 1} + e^{- 2} : \frac{1}{e} + \frac{1}{e ^{2}}

= \frac{e ^{4}}{\frac{1}{e} + \frac{1}{e ^{2}}}

Join

\frac{1}{e} + \frac{1}{e ^{2}} : \frac{e + 1}{e ^{2}}

= \frac{e ^{4}}{\frac{e + 1}{e ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{e ^{4} e ^{2}}{e + 1}

e^{4} e^{2} = e^{6}

= \frac{e ^{6}}{e + 1}

(448)^{3}

\frac{5 x + 3 y}{2 ( x + y )} - \frac{3 x - 5 y}{8 ( x + y )}

x^{3} \cdot x^{3} \cdot x^{3}

- 3 \cdot (- 9)

\frac{( 3 ^{2} ) ^{4}}{3 ( 3 ) ( 3 ^{4} )}

What is (e^4)/(e^{-1)+e^{-2}} ?
The solution to (e^4)/(e^{-1)+e^{-2}} is (e^6)/(e+1)