What is factor n^2-3n-4 ?

The solution to factor n^2-3n-4 is (n+1)(n-4)

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factor n^2-3n-4

factor

n^{2} - 3 n - 4

(n + 1) (n - 4)

Solution steps

n^{2} - 3 n - 4

Break the expression into groups

= (n^{2} + n) + (- 4 n - 4)

Factor out

n

from

n^{2} + n : n (n + 1)

Factor out

- 4

from

- 4 n - 4 : - 4 (n + 1)

= n (n + 1) - 4 (n + 1)

Factor out common term

n + 1

= (n + 1) (n - 4)

9 x^{4} y^{2} + 5 x^{3} y - 7 x^{2} y^{5} - 8 x y

- 2 x - 2 y^{4} \cdot (- x^{5} y - 3) - 5

- 6 (x - 7)

\frac{5}{3} + \frac{3}{5}

\frac{3}{10} \cdot 4 \frac{5}{6}