What is (x^2-4)/(x^2+4)*(x+2)/(x-2) ?

The solution to (x^2-4)/(x^2+4)*(x+2)/(x-2) is ((x+2)^2)/(x^2+4)

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simplify (x^2-4)/(x^2+4)*(x+2)/(x-2)

simplify

\frac{x ^{2} - 4}{x ^{2} + 4} \cdot \frac{x + 2}{x - 2}

\frac{( x + 2 ) ^{2}}{x ^{2} + 4}

Solution steps

\frac{x ^{2} - 4}{x ^{2} + 4} \cdot \frac{x + 2}{x - 2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x ^{2} - 4 ) ( x + 2 )}{( x ^{2} + 4 ) ( x - 2 )}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 ) ( x + 2 )}{( x ^{2} + 4 ) ( x - 2 )}

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= \frac{( x + 2 ) ^{2} ( x - 2 )}{( x ^{2} + 4 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{( x + 2 ) ^{2}}{x ^{2} + 4}

(n - 8)^{2}

\frac{5 120}{6 40}

20 - 9 x + 4 y + 7 - x

(x^{2} - x + 1) (x^{2} + x + 1)

(3 - 2)^{2}

What is (x^2-4)/(x^2+4)*(x+2)/(x-2) ?
The solution to (x^2-4)/(x^2+4)*(x+2)/(x-2) is ((x+2)^2)/(x^2+4)