What is 2(1/2 x^2+8)^2-8 ?

The solution to 2(1/2 x^2+8)^2-8 is (x^4)/2+16x^2+120

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simplify 2(1/2 x^2+8)^2-8

simplify

2 (\frac{1}{2} x^{2} + 8)^{2} - 8

\frac{x ^{4}}{2} + 16 x^{2} + 120

Solution steps

2 (\frac{1}{2} x^{2} + 8)^{2} - 8

(\frac{1}{2} x^{2} + 8)^{2} = \frac{x ^{4}}{4} + 8 x^{2} + 64

= 2 (\frac{x ^{4}}{4} + 8 x^{2} + 64) - 8

Expand

2 (\frac{x ^{4}}{4} + 8 x^{2} + 64) : \frac{x ^{4}}{2} + 16 x^{2} + 128

= \frac{x ^{4}}{2} + 16 x^{2} + 128 - 8

Add/Subtract the numbers:

128 - 8 = 120

= \frac{x ^{4}}{2} + 16 x^{2} + 120

\frac{21}{60}

x^{4} - 10 x^{2} y^{2} + 25 y^{4}

\frac{1}{3 + 2}

\frac{7 x}{x ^{2} - 4} + \frac{2}{x + 2}

\frac{\frac{2 b - 10}{3}}{\frac{b - 5}{9}}

What is 2(1/2 x^2+8)^2-8 ?
The solution to 2(1/2 x^2+8)^2-8 is (x^4)/2+16x^2+120