What is (7x^2+29x+24)/(5x^2+19x+12) ?

The solution to (7x^2+29x+24)/(5x^2+19x+12) is (7x+8)/(5x+4)

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simplify (7x^2+29x+24)/(5x^2+19x+12)

simplify

\frac{7 x ^{2} + 29 x + 24}{5 x ^{2} + 19 x + 12}

\frac{7 x + 8}{5 x + 4}

Solution steps

\frac{7 x ^{2} + 29 x + 24}{5 x ^{2} + 19 x + 12}

Factor

7 x^{2} + 29 x + 24 : (7 x + 8) (x + 3)

= \frac{( 7 x + 8 ) ( x + 3 )}{5 x ^{2} + 19 x + 12}

Factor

5 x^{2} + 19 x + 12 : (5 x + 4) (x + 3)

= \frac{( 7 x + 8 ) ( x + 3 )}{( 5 x + 4 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{7 x + 8}{5 x + 4}

(- 7)^{- 3}

(\frac{4}{2})^{3}

sin (x) (1 + cot^{2} (x))

\frac{7}{5} + \frac{3}{5}

What is (7x^2+29x+24)/(5x^2+19x+12) ?
The solution to (7x^2+29x+24)/(5x^2+19x+12) is (7x+8)/(5x+4)