What is log_{10}(e^{(a+bx)}) ?

The solution to log_{10}(e^{(a+bx)}) is log_{10}(e)(a+bx)

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simplify log_{10}(e^{(a+bx)})

simplify

lo g_{10} (e^{(a + b x)})

lo g_{10} (e) (a + b x)

Solution steps

lo g_{10} (e^{a + b x})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= lo g_{10} (e) (b x + a)

(1 - 2 i) \cdot (1 + 2 i)

15 x - 24

π \cdot 7^{2}

(\frac{1}{3 x} - 2 x)^{16}

4 (3 m + 2 n) (3 m + 2 n)

What is log_{10}(e^{(a+bx)}) ?
The solution to log_{10}(e^{(a+bx)}) is log_{10}(e)(a+bx)