What is (x+1)(x^2+x+1)(x-1)(x^2-x+1)+1 ?

The solution to (x+1)(x^2+x+1)(x-1)(x^2-x+1)+1 is x^6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x+1)(x^2+x+1)(x-1)(x^2-x+1)+1

simplify

(x + 1) (x^{2} + x + 1) (x - 1) (x^{2} - x + 1) + 1

x^{6}

Solution steps

(x + 1) (x^{2} + x + 1) (x - 1) (x^{2} - x + 1) + 1

Expand

(x + 1) (x^{2} + x + 1) (x - 1) (x^{2} - x + 1) : x^{6} - 1

= x^{6} - 1 + 1

Add the numbers:

- 1 + 1 = 0

= x^{6}

\frac{1 5 ^{2} \cdot 25 \cdot 49}{3 5 ^{2} \cdot 4 5 ^{2}}

\frac{2}{9} - \frac{4}{15} + 2

\frac{60}{5}

\frac{x}{x + 4} - \frac{2 x}{x + 2}

What is (x+1)(x^2+x+1)(x-1)(x^2-x+1)+1 ?
The solution to (x+1)(x^2+x+1)(x-1)(x^2-x+1)+1 is x^6