What is (2x^2-x-3)/(3x^2+2x-1) ?

The solution to (2x^2-x-3)/(3x^2+2x-1) is (2x-3)/(3x-1)

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simplify (2x^2-x-3)/(3x^2+2x-1)

simplify

\frac{2 x ^{2} - x - 3}{3 x ^{2} + 2 x - 1}

\frac{2 x - 3}{3 x - 1}

Solution steps

\frac{2 x ^{2} - x - 3}{3 x ^{2} + 2 x - 1}

Factor

2 x^{2} - x - 3 : (x + 1) (2 x - 3)

= \frac{( x + 1 ) ( 2 x - 3 )}{3 x ^{2} + 2 x - 1}

Factor

3 x^{2} + 2 x - 1 : (3 x - 1) (x + 1)

= \frac{( x + 1 ) ( 2 x - 3 )}{( 3 x - 1 ) ( x + 1 )}

Cancel the common factor:

x + 1

= \frac{2 x - 3}{3 x - 1}

7 - (2110)

D^{4} x [cos (x)]

6 - (3 x - 2 i)^{2}

\frac{8}{2 x - 10} + \frac{3}{x}

\frac{1}{4} - \frac{3}{8} + \frac{7}{8}

What is (2x^2-x-3)/(3x^2+2x-1) ?
The solution to (2x^2-x-3)/(3x^2+2x-1) is (2x-3)/(3x-1)