What are the solutions to the equation x^2-12x+12=0 ?

The solutions to the equation x^2-12x+12=0 are x=2(3+sqrt(6)),x=2(3-sqrt(6))

Find the zeros of x^2-12x+12=0

The zeros of x^2-12x+12=0 are x=2(3+sqrt(6)),x=2(3-sqrt(6))

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x^{2} - 12 x + 12 = 0

x = 2 (3 + 6), x = 2 (3 - 6)

Decimal Notation

x = 10.89897 \dots, x = 1.10102 \dots

Solution steps

x^{2} - 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 12 = 46

x_{1, 2} = \frac{- ( - 12 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 6}{2 \cdot 1} : 2 (3 + 6)

x = \frac{- ( - 12 ) - 4 6}{2 \cdot 1} : 2 (3 - 6)

The solutions to the quadratic equation are:

x = 2 (3 + 6), x = 2 (3 - 6)

42 - 35 + 42 + 85

7 - (3.1 - 0.1 y) = 3 - 0.2 y

9 x^{2} - 16 y^{2}

- 5 - 4 x = 3 - 2 x - x^{2}

ln (e^{10})

What are the solutions to the equation x^2-12x+12=0 ?
The solutions to the equation x^2-12x+12=0 are x=2(3+sqrt(6)),x=2(3-sqrt(6))
Find the zeros of x^2-12x+12=0
The zeros of x^2-12x+12=0 are x=2(3+sqrt(6)),x=2(3-sqrt(6))