What is (5+12i)+[(10-8i)+[(6+3i)-(7+2i)]] ?

The solution to (5+12i)+[(10-8i)+[(6+3i)-(7+2i)]] is 14+5i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (5+12i)+[(10-8i)+[(6+3i)-(7+2i)]]

simplify

(5 + 12 i) + [(10 - 8 i) + [(6 + 3 i) - (7 + 2 i)]]

14 + 5 i

Solution steps

(5 + 12 i) + ((10 - 8 i) + ((6 + 3 i) - (7 + 2 i)))

Simplify

(5 + 12 i) + ((10 - 8 i) + ((6 + 3 i) - (7 + 2 i))) : 5 + 12 i + 10 - 8 i + 6 + 3 i - (7 + 2 i)

= 5 + 12 i + 10 - 8 i + 6 + 3 i - (7 + 2 i)

Group like terms

= 12 i - 8 i + 3 i - (7 + 2 i) + 5 + 10 + 6

Add similar elements:

12 i - 8 i + 3 i = 7 i

= 7 i - (7 + 2 i) + 5 + 10 + 6

Add the numbers:

5 + 10 + 6 = 21

= 7 i - (7 + 2 i) + 21

Remove parentheses:

- (a + bi) = - a - bi

= 7 i + - 7 - 2 i + 21

Group like terms

= 7 i - 2 i - 7 + 21

Add similar elements:

7 i - 2 i = 5 i

= 5 i - 7 + 21

Add the numbers:

- 7 + 21 = 14

= 5 i + 14

Rewrite in standard complex form:

14 + 5 i

= 14 + 5 i

2 sin (3 θ) cos (3 θ)

a b^{3}

(x + 5) (x - 5) (x^{2} + 25) (x^{4} + 625) + 62 5^{2}

9 x^{2} + \frac{3}{2} x + \frac{1}{16}

(5 - - 9) (- 1 + - 4)

What is (5+12i)+[(10-8i)+[(6+3i)-(7+2i)]] ?
The solution to (5+12i)+[(10-8i)+[(6+3i)-(7+2i)]] is 14+5i