What is (3^2)^3*(2*3^5)^{-2}*(18)^2 ?

The solution to (3^2)^3*(2*3^5)^{-2}*(18)^2 is 1

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simplify (3^2)^3(23^5)^{-2}*(18)^2

simplify

(3^{2})^{3} \cdot (2 \cdot 3^{5})^{- 2} \cdot (18)^{2}

1

Solution steps

(3^{2})^{3} (2 \cdot 3^{5})^{- 2} \cdot 1 8^{2}

(3^{2})^{3} = 729

= 729 (2 \cdot 3^{5})^{- 2} \cdot 1 8^{2}

(2 \cdot 3^{5})^{- 2} = \frac{1}{236196}

= 729 \cdot \frac{1}{236196} \cdot 1 8^{2}

1 8^{2} = 324

= 729 \cdot \frac{1}{236196} \cdot 324

Multiply the numbers:

729 \cdot 324 = 236196

= 236196 \cdot \frac{1}{236196}

= \frac{1}{236196} \cdot 236196

Convert element to fraction:

236196 = \frac{236196}{1}

= \frac{1}{236196} \cdot \frac{236196}{1}

Cross-cancel common factor:

236196

= 1

1 - x^{8}

2 + \frac{1}{3 + \frac{1}{1 + \frac{1}{1 + \frac{1}{2}}}}

(6 + 2)^{2}

(6 - 2 x)^{4}

\frac{( 8 ^{3} \cdot 36 - 2 ^{5} + 2 ^{3} + 16 + 2 )}{3}

What is (3^2)^3*(2*3^5)^{-2}*(18)^2 ?
The solution to (3^2)^3*(2*3^5)^{-2}*(18)^2 is 1