What is (x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4) ?

The solution to (x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4) is ((x-4)x(x-1))/(2(x+4))

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simplify (x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4)

simplify

\frac{x ^{2} - 16}{2 x + 8} \cdot \frac{x ^{3} - 2 x ^{2} + x}{x ^{2} + 3 x - 4}

\frac{( x - 4 ) x ( x - 1 )}{2 ( x + 4 )}

Solution steps

\frac{x ^{2} - 16}{2 x + 8} \cdot \frac{x ^{3} - 2 x ^{2} + x}{x ^{2} + 3 x - 4}

Cancel

\frac{x ^{2} - 16}{2 x + 8} : \frac{x - 4}{2}

= \frac{x - 4}{2} \cdot \frac{x ^{3} - 2 x ^{2} + x}{x ^{2} + 3 x - 4}

Cancel

\frac{x ^{3} - 2 x ^{2} + x}{x ^{2} + 3 x - 4} : \frac{x ( x - 1 )}{x + 4}

= \frac{x - 4}{2} \cdot \frac{x ( x - 1 )}{x + 4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x - 4 ) x ( x - 1 )}{2 ( x + 4 )}

(\frac{1}{2} + \frac{i}{2})^{2021}

(3 x + 2) (2 x + 5)

\frac{121}{25}

6 (18 + 8)

\frac{a - 1}{a ^{2} + 5 a + 6} + \frac{a + 2}{a ^{2} - 9}

What is (x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4) ?
The solution to (x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4) is ((x-4)x(x-1))/(2(x+4))