What is (\frac{n+3)/(2n-6)}{(n+3)/(3n-9)} ?

The solution to (\frac{n+3)/(2n-6)}{(n+3)/(3n-9)} is 3/2

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simplify (\frac{n+3)/(2n-6)}{(n+3)/(3n-9)}

simplify

\frac{\frac{n + 3}{2 n - 6}}{\frac{n + 3}{3 n - 9}}

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\frac{\frac{n + 3}{2 n - 6}}{\frac{n + 3}{3 n - 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( n + 3 ) ( 3 n - 9 )}{( 2 n - 6 ) ( n + 3 )}

Cancel the common factor:

n + 3

= \frac{3 n - 9}{2 n - 6}

Factor

3 n - 9 : 3 (n - 3)

= \frac{3 ( n - 3 )}{2 n - 6}

Factor

2 n - 6 : 2 (n - 3)

= \frac{3 ( n - 3 )}{2 ( n - 3 )}

Cancel the common factor:

n - 3

= \frac{3}{2}

(x + 1)^{2} - 9

a - (b + a) + (- a + b) - (- a + 2 b)

(6 i - 2) + (3 - 4 i)

4 x^{3}

(x^{2} + \frac{3}{x ^{3}})^{14}

What is (\frac{n+3)/(2n-6)}{(n+3)/(3n-9)} ?
The solution to (\frac{n+3)/(2n-6)}{(n+3)/(3n-9)} is 3/2