What is expand (x+y+2)(3x+2y-4) ?

The solution to expand (x+y+2)(3x+2y-4) is 3x^2+5xy+2x+2y^2-8

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expand (x+y+2)(3x+2y-4)

expand

(x + y + 2) (3 x + 2 y - 4)

3 x^{2} + 5 x y + 2 x + 2 y^{2} - 8

Solution steps

(x + y + 2) (3 x + 2 y - 4)

Distribute parentheses

= x \cdot 3 x + x \cdot 2 y + x (- 4) + y \cdot 3 x + y \cdot 2 y + y (- 4) + 2 \cdot 3 x + 2 \cdot 2 y + 2 (- 4)

Simplify

x \cdot 3 x + x \cdot 2 y + x (- 4) + y \cdot 3 x + y \cdot 2 y + y (- 4) + 2 \cdot 3 x + 2 \cdot 2 y + 2 (- 4) : 3 x^{2} + 5 x y + 2 x + 2 y^{2} - 8

= 3 x^{2} + 5 x y + 2 x + 2 y^{2} - 8

320 x^{4} y^{9}

\frac{2}{x + 3} + \frac{4}{( x + 3 ) ^{2}}

\frac{3}{4} 176 - \frac{2}{3} 45 + \frac{1}{8} 320 + \frac{1}{5} 275

x \to \infty lim (\frac{0}{x})

What is expand (x+y+2)(3x+2y-4) ?
The solution to expand (x+y+2)(3x+2y-4) is 3x^2+5xy+2x+2y^2-8