What is (12xy^2+20x^2yz-10y^2)/(10y^2) ?

The solution to (12xy^2+20x^2yz-10y^2)/(10y^2) is (6xy+10x^2z-5y)/(5y)

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simplify (12xy^2+20x^2yz-10y^2)/(10y^2)

simplify

\frac{12 x y ^{2} + 20 x ^{2} yz - 10 y ^{2}}{10 y ^{2}}

\frac{6 x y + 10 x ^{2} z - 5 y}{5 y}

Solution steps

\frac{12 x y ^{2} + 20 x ^{2} yz - 10 y ^{2}}{10 y ^{2}}

Factor out common term

2 y : 2 y (6 x y + 10 x^{2} z - 5 y)

= \frac{2 y ( 6 x y + 10 x ^{2} z - 5 y )}{10 y ^{2}}

Factor the number:

10 = 2 \cdot 5

= \frac{2 y ( 6 x y + 10 x ^{2} z - 5 y )}{2 \cdot 5 y ^{2}}

Cancel the common factor:

2

= \frac{y ( 6 x y + 10 x ^{2} z - 5 y )}{5 y ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

y^{2} = yy

= \frac{y ( 6 x y + 10 x ^{2} z - 5 y )}{5 yy}

Cancel the common factor:

y

= \frac{6 x y + 10 x ^{2} z - 5 y}{5 y}

(3 + 5 i) (2 - 7 i)

5^{3} \cdot 5^{2}

\frac{csc ( θ )}{cot ( θ )}

\frac{a ^{2} - 4 a + 4}{a ^{2} + ab - 2 a - 2 b}

\frac{75}{12}

What is (12xy^2+20x^2yz-10y^2)/(10y^2) ?
The solution to (12xy^2+20x^2yz-10y^2)/(10y^2) is (6xy+10x^2z-5y)/(5y)