What are the solutions to the equation d^2+10d+24=0 ?

The solutions to the equation d^2+10d+24=0 are d=-4,d=-6

Find the zeros of d^2+10d+24=0

The zeros of d^2+10d+24=0 are d=-4,d=-6

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d^{2} + 10 d + 24 = 0

d = - 4, d = - 6

Solution steps

d^{2} + 10 d + 24 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

d_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 10 + 2}{2 \cdot 1}, d_{2} = \frac{- 10 - 2}{2 \cdot 1}

d = \frac{- 10 + 2}{2 \cdot 1} : - 4

d = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

d = - 4, d = - 6

9 h^{2} - 64

- 9 (x + 2) - 3 x = - 102

12 x - 6 x^{2} = 4

- x - 25 = - 5 x + 51

6 x^{2} - x - 1 < 0

What are the solutions to the equation d^2+10d+24=0 ?
The solutions to the equation d^2+10d+24=0 are d=-4,d=-6
Find the zeros of d^2+10d+24=0
The zeros of d^2+10d+24=0 are d=-4,d=-6