What is 4(x^{-3}y^4)(-3xy^2)^2 ?

The solution to 4(x^{-3}y^4)(-3xy^2)^2 is (36y^8)/x

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simplify 4(x^{-3}y^4)(-3xy^2)^2

simplify

4 (x^{- 3} y^{4}) (- 3 x y^{2})^{2}

\frac{36 y ^{8}}{x}

Solution steps

4 (x^{- 3} y^{4}) (- 3 x y^{2})^{2}

Simplify

x^{- 3} y^{4} : \frac{y ^{4}}{x ^{3}}

= 4 \cdot \frac{y ^{4}}{x ^{3}} (- 3 x y^{2})^{2}

Simplify

(- 3 x y^{2})^{2} : 9 x^{2} y^{4}

= 4 \cdot \frac{y ^{4}}{x ^{3}} \cdot 9 x^{2} y^{4}

Multiply the numbers:

4 \cdot 9 = 36

= 36 \cdot \frac{y ^{4}}{x ^{3}} x^{2} y^{4}

= 36 x^{2} y^{4} \frac{y ^{4}}{x ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{36 x ^{2} y ^{4} y ^{4}}{x ^{3}}

Simplify

\frac{x ^{2}}{x ^{3}} : \frac{1}{x}

= \frac{36 y ^{4} y ^{4}}{x}

Simplify

y^{4} y^{4} : y^{8}

= \frac{36 y ^{8}}{x}

(3 y - 1)^{2}

\frac{33}{5 \times ( - \frac{81}{3} )}

(cos (x))^{2} - (sin (x))^{2}

\frac{5}{3 3}

What is 4(x^{-3}y^4)(-3xy^2)^2 ?
The solution to 4(x^{-3}y^4)(-3xy^2)^2 is (36y^8)/x