What is x/(x^2+3x+2)-1/((x+2)(x+1)) ?

The solution to x/(x^2+3x+2)-1/((x+2)(x+1)) is (x-1)/((x+1)(x+2))

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simplify x/(x^2+3x+2)-1/((x+2)(x+1))

simplify

\frac{x}{x ^{2} + 3 x + 2} - \frac{1}{( x + 2 ) ( x + 1 )}

\frac{x - 1}{( x + 1 ) ( x + 2 )}

Solution steps

\frac{x}{x ^{2} + 3 x + 2} - \frac{1}{( x + 2 ) ( x + 1 )}

Least Common Multiplier of

x^{2} + 3 x + 2, (x + 2) (x + 1) : (x + 1) (x + 2)

Adjust Fractions based on the LCM

= \frac{x}{( x + 1 ) ( x + 2 )} - \frac{1}{( x + 1 ) ( x + 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x - 1}{( x + 1 ) ( x + 2 )}

\frac{a ^{2} - 1}{( a - 1 ) ^{2}}

14 0^{2}

(sin (x) + cos (x))^{2} - sin (2 x)

(a + b) m^{2} + (a + b) n

1 + lo g_{2} (50)

What is x/(x^2+3x+2)-1/((x+2)(x+1)) ?
The solution to x/(x^2+3x+2)-1/((x+2)(x+1)) is (x-1)/((x+1)(x+2))