What is 2cos^2(2x)-2sin^2(2x) ?

The solution to 2cos^2(2x)-2sin^2(2x) is 2cos(4x)

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simplify 2cos^2(2x)-2sin^2(2x)

simplify

2 cos^{2} (2 x) - 2 sin^{2} (2 x)

2 cos (4 x)

Solution steps

2 cos^{2} (2 x) - 2 sin^{2} (2 x)

Rewrite using trig identities

= 2 cos (4 x)

(x + 1)^{2} + (x + 4)^{2} - 2 x^{2} - 10 x

\frac{sec ( θ )}{cos ( θ )}

(a + b)^{20}

(3.95)^{3}

cos (x) \cdot (- sin (x))

What is 2cos^2(2x)-2sin^2(2x) ?
The solution to 2cos^2(2x)-2sin^2(2x) is 2cos(4x)