What is (x/2-1/(x+1))/(x/2+\frac{2x+3){x+1}} ?

The solution to (x/2-1/(x+1))/(x/2+\frac{2x+3){x+1}} is (x-1)/(x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x/2-1/(x+1))/(x/2+\frac{2x+3){x+1}}

simplify

\frac{\frac{x}{2} - \frac{1}{x + 1}}{\frac{x}{2} + \frac{2 x + 3}{x + 1}}

\frac{x - 1}{x + 3}

Solution steps

\frac{\frac{x}{2} - \frac{1}{x + 1}}{\frac{x}{2} + \frac{2 x + 3}{x + 1}}

Join

\frac{x}{2} - \frac{1}{x + 1} : \frac{x ^{2} + x - 2}{2 ( x + 1 )}

= \frac{\frac{x ^{2} + x - 2}{2 ( x + 1 )}}{\frac{x}{2} + \frac{2 x + 3}{x + 1}}

Join

\frac{x}{2} + \frac{2 x + 3}{x + 1} : \frac{x ^{2} + 5 x + 6}{2 ( x + 1 )}

= \frac{\frac{x ^{2} + x - 2}{2 ( x + 1 )}}{\frac{x ^{2} + 5 x + 6}{2 ( x + 1 )}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + x - 2 ) \cdot 2 ( x + 1 )}{2 ( x + 1 ) ( x ^{2} + 5 x + 6 )}

Cancel

\frac{( x ^{2} + x - 2 ) \cdot 2 ( x + 1 )}{2 ( x + 1 ) ( x ^{2} + 5 x + 6 )} : \frac{x - 1}{x + 3}

= \frac{x - 1}{x + 3}

4 x y^{6} x y^{2}

lo g_{2} (52)

3 cos^{2} (3 x) + 3 sin^{2} (3 x)

cos^{2} (x) (sec^{2} (x) - 1)

What is (x/2-1/(x+1))/(x/2+\frac{2x+3){x+1}} ?
The solution to (x/2-1/(x+1))/(x/2+\frac{2x+3){x+1}} is (x-1)/(x+3)