What is 1/(x-1)-2/(x^2-1) ?

The solution to 1/(x-1)-2/(x^2-1) is 1/(x+1)

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simplify 1/(x-1)-2/(x^2-1)

simplify

\frac{1}{x - 1} - \frac{2}{x ^{2} - 1}

\frac{1}{x + 1}

Solution steps

\frac{1}{x - 1} - \frac{2}{x ^{2} - 1}

Least Common Multiplier of

x - 1, x^{2} - 1 : (x - 1) (x + 1)

Adjust Fractions based on the LCM

= \frac{x + 1}{( x - 1 ) ( x + 1 )} - \frac{2}{( x - 1 ) ( x + 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x + 1 - 2}{( x - 1 ) ( x + 1 )}

Subtract the numbers:

1 - 2 = - 1

= \frac{x - 1}{( x - 1 ) ( x + 1 )}

Cancel the common factor:

x - 1

= \frac{1}{x + 1}

3 \cdot \frac{2}{2}

(4 - 2 i)^{3}

x^{2} \cdot (- 2)

(2 x + 3) (4 x^{2} - 6 x + 9) - (2 x) (4 x^{2})

\frac{5 - 3 m}{- 3 m + 5}