What are the solutions to the equation x^2+12x=20 ?

The solutions to the equation x^2+12x=20 are x=2(sqrt(14)-3),x=-2(3+sqrt(14))

Find the zeros of x^2+12x=20

The zeros of x^2+12x=20 are x=2(sqrt(14)-3),x=-2(3+sqrt(14))

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x^{2} + 12 x = 20

x = 2 (14 - 3), x = - 2 (3 + 14)

Decimal Notation

x = 1.48331 \dots, x = - 13.48331 \dots

Solution steps

x^{2} + 12 x = 20

Move

20

to the left side

x^{2} + 12 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 20) = 414

x_{1, 2} = \frac{- 12 \pm 4 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 14}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 14}{2 \cdot 1}

x = \frac{- 12 + 4 14}{2 \cdot 1} : 2 (14 - 3)

x = \frac{- 12 - 4 14}{2 \cdot 1} : - 2 (3 + 14)

The solutions to the quadratic equation are:

x = 2 (14 - 3), x = - 2 (3 + 14)

(\frac{8}{7})^{- 2}

(\frac{2 x ^{4}}{3})^{3}

\frac{1}{6} - \frac{1}{12}

(x^{2} + 5 x)^{2} + 7 (x^{2} + 5 x) + 6

- 8 x^{2} = 0

What are the solutions to the equation x^2+12x=20 ?
The solutions to the equation x^2+12x=20 are x=2(sqrt(14)-3),x=-2(3+sqrt(14))
Find the zeros of x^2+12x=20
The zeros of x^2+12x=20 are x=2(sqrt(14)-3),x=-2(3+sqrt(14))