What is \sqrt[3]{(x^2+y^2)^4} ?

The solution to \sqrt[3]{(x^2+y^2)^4} is (x^2+y^2)\sqrt[3]{x^2+y^2}

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simplify \sqrt[3]{(x^2+y^2)^4}

simplify

Solution steps

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x^{2} + y^{2})^{3 + 1} = (x^{2} + y^{2})^{3} (x^{2} + y^{2})

Apply radical rule:

assuming

a \geq 0, b \geq 0

Apply radical rule:

n

is odd

\frac{\frac{( a ^{2} b )}{( 2 a )}}{( a b ^{2} )}

9 \cdot 27

1.04

10 x + 10 y

\frac{18}{2}

What is \sqrt[3]{(x^2+y^2)^4} ?
The solution to \sqrt[3]{(x^2+y^2)^4} is (x^2+y^2)\sqrt[3]{x^2+y^2}