What are the solutions to the equation x^2-x-1=0 ?

The solutions to the equation x^2-x-1=0 are x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Find the zeros of x^2-x-1=0

The zeros of x^2-x-1=0 are x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

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x^{2} - x - 1 = 0

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Decimal Notation

x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 1) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : \frac{1 + 5}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : \frac{1 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

3 + 11 (9) - 9 (11)

x^{2} - 12 x + 28 = 0

∣ 5 - 2 x ∣ = 11

\frac{1}{x + 1} + \frac{1}{x + 8} \leq \frac{1}{x + 9}

14 r - 11 > - 227

What are the solutions to the equation x^2-x-1=0 ?
The solutions to the equation x^2-x-1=0 are x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Find the zeros of x^2-x-1=0
The zeros of x^2-x-1=0 are x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2