What is (-15x^2-8y^2+22xy)/(2y-3x) ?

The solution to (-15x^2-8y^2+22xy)/(2y-3x) is 5x-4y

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simplify (-15x^2-8y^2+22xy)/(2y-3x)

simplify

\frac{- 15 x ^{2} - 8 y ^{2} + 22 x y}{2 y - 3 x}

5 x - 4 y

Solution steps

\frac{- 15 x ^{2} - 8 y ^{2} + 22 x y}{2 y - 3 x}

Factor out

- 1 : - (15 x^{2} + 8 y^{2} - 22 x y)

= \frac{- ( 15 x ^{2} + 8 y ^{2} - 22 x y )}{2 y - 3 x}

Factor

15 x^{2} + 8 y^{2} - 22 x y : (3 x - 2 y) (5 x - 4 y)

= \frac{- ( 3 x - 2 y ) ( 5 x - 4 y )}{2 y - 3 x}

2 y - 3 x = - (3 x - 2 y)

= \frac{- ( 3 x - 2 y ) ( 5 x - 4 y )}{- ( 3 x - 2 y )}

Cancel the common factor:

3 x - 2 y

= \frac{- ( 5 x - 4 y )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5 x - 4 y}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 5 x - 4 y

cos (θ) sec (θ)

1 + 3.3 lo g_{10} (20)

(\frac{x ^{3}}{2} - \frac{2}{x ^{2}})^{5}

17 - 3 (x + 2)

3 \cdot lo g_{10} (10)

What is (-15x^2-8y^2+22xy)/(2y-3x) ?
The solution to (-15x^2-8y^2+22xy)/(2y-3x) is 5x-4y