What is (10c^6d^{-5})(2c^{-5}d^4) ?

The solution to (10c^6d^{-5})(2c^{-5}d^4) is (20c)/d

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simplify (10c^6d^{-5})(2c^{-5}d^4)

simplify

(10 c^{6} d^{- 5}) (2 c^{- 5} d^{4})

\frac{20 c}{d}

Solution steps

(10 c^{6} d^{- 5}) (2 c^{- 5} d^{4})

Simplify

10 c^{6} d^{- 5} : \frac{10 c ^{6}}{d ^{5}}

= \frac{10 c ^{6}}{d ^{5}} \cdot 2 c^{- 5} d^{4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

c^{- 5} = \frac{1}{c ^{5}}

= \frac{10 c ^{6}}{d ^{5}} \cdot 2 \cdot \frac{1}{c ^{5}} d^{4}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{10 c ^{6} \cdot 2 \cdot 1 \cdot d ^{4}}{d ^{5} c ^{5}}

Multiply the numbers:

10 \cdot 2 \cdot 1 = 20

= \frac{20 c ^{6} d ^{4}}{d ^{5} c ^{5}}

Simplify

\frac{c ^{6}}{c ^{5}} : c

= \frac{20 c d ^{4}}{d ^{5}}

Simplify

\frac{d ^{4}}{d ^{5}} : \frac{1}{d}

= \frac{20 c}{d}

(2 + 4 i) (3 - i)

\frac{sin ^{2} ( θ )}{tan ^{2} ( θ )}

20 a^{6} b^{5} c^{8} d

(x - 1) (x - 2) (x - 3) (x - 4) (x - 5)

\frac{5 3 + 2}{3 + 1}

What is (10c^6d^{-5})(2c^{-5}d^4) ?
The solution to (10c^6d^{-5})(2c^{-5}d^4) is (20c)/d