What is (9-2i)(10i-5) ?

The solution to (9-2i)(10i-5) is -25+100i

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simplify (9-2i)(10i-5)

simplify

(9 - 2 i) (10 i - 5)

- 25 + 100 i

Solution steps

(9 - 2 i) (10 i - 5)

Rewrite

10 i - 5

in standard complex form:

- 5 + 10 i

= (9 - 2 i) (- 5 + 10 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (9 (- 5) - (- 2) \cdot 10) + (9 \cdot 10 - 2 (- 5)) i

Simplify

(9 (- 5) - (- 2) \cdot 10) + (9 \cdot 10 - 2 (- 5)) i : - 25 + 100 i

= - 25 + 100 i

\frac{\frac{2}{2}}{\frac{2 - 1}{2}} - 4

7 x^{- 1}

(a + b + c + d)^{3}

4 (x + 3) + 5 (x + 2)

5 (3 t - 4) - (t^{2} + 2) - 2 t (t - 3)