What is \sqrt[3]{(2x^4y^4)/(9x)} ?

The solution to \sqrt[3]{(2x^4y^4)/(9x)} is (\sqrt[3]{2}xy\sqrt[3]{y})/(\sqrt[3]{9)}

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simplify \sqrt[3]{(2x^4y^4)/(9x)}

simplify

Solution steps

Cancel

\frac{2 x ^{4} y ^{4}}{9 x} : \frac{2 x ^{3} y ^{4}}{9}

Apply radical rule:

assuming

a \geq 0, b \geq 0

Simplify

\frac{2 5}{5}

- 56 (32 + 10)

3 x^{2} + 6 - 2 x + 5 x - 4 x^{2} + 9

cos (x) (sec (x) - cos (x))

\frac{cos ( - x )}{tan ( - x )} + sin (- x)

What is \sqrt[3]{(2x^4y^4)/(9x)} ?
The solution to \sqrt[3]{(2x^4y^4)/(9x)} is (\sqrt[3]{2}xy\sqrt[3]{y})/(\sqrt[3]{9)}