What is 4x(x+1)-(3x-8)(x+4) ?

The solution to 4x(x+1)-(3x-8)(x+4) is x^2+32

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simplify 4x(x+1)-(3x-8)(x+4)

simplify

4 x (x + 1) - (3 x - 8) (x + 4)

x^{2} + 32

Solution steps

4 x (x + 1) - (3 x - 8) (x + 4)

Expand

4 x (x + 1) : 4 x^{2} + 4 x

= 4 x^{2} + 4 x - (3 x - 8) (x + 4)

Expand

- (3 x - 8) (x + 4) : - 3 x^{2} - 4 x + 32

= 4 x^{2} + 4 x - 3 x^{2} - 4 x + 32

Group like terms

= 4 x^{2} - 3 x^{2} + 4 x - 4 x + 32

Add similar elements:

4 x^{2} - 3 x^{2} = x^{2}

= x^{2} + 4 x - 4 x + 32

Add similar elements:

4 x - 4 x = 0

= x^{2} + 32

(x^{2} - 4) (3 x^{2} + 2 x - 1)

1 \frac{3}{2}

\frac{2}{3} (x^{2} + 1)^{\frac{3}{2}}