What is factor 16x^4-4x^2-4x-1 ?

The solution to factor 16x^4-4x^2-4x-1 is (4x^2+2x+1)(4x^2-2x-1)

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factor 16x^4-4x^2-4x-1

factor

16 x^{4} - 4 x^{2} - 4 x - 1

(4 x^{2} + 2 x + 1) (4 x^{2} - 2 x - 1)

Solution steps

16 x^{4} - 4 x^{2} - 4 x - 1

Factor

- 4 x^{2} - 4 x - 1 : - (2 x + 1)^{2}

= 16 x^{4} - (2 x + 1)^{2}

Simplify

16 x^{4} : (4 x^{2})^{2}

= (4 x^{2})^{2} - (2 x + 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x^{2})^{2} - (2 x + 1)^{2} = (4 x^{2} + (2 x + 1)) (4 x^{2} - (2 x + 1))

= (4 x^{2} + (2 x + 1)) (4 x^{2} - (2 x + 1))

Simplify

(4 x^{2} + (2 x + 1)) (4 x^{2} - (2 x + 1)) : (4 x^{2} + 2 x + 1) (4 x^{2} - 2 x - 1)

= (4 x^{2} + 2 x + 1) (4 x^{2} - 2 x - 1)

(3 x + 3)^{3}

(2.2)^{2}

lo g_{4} (32) - lo g_{9} (27)

12 \cdot 1 0^{- 6}

What is factor 16x^4-4x^2-4x-1 ?
The solution to factor 16x^4-4x^2-4x-1 is (4x^2+2x+1)(4x^2-2x-1)