What is (6+7i)/(8-i) ?

The solution to (6+7i)/(8-i) is 41/65+62/65 i

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simplify (6+7i)/(8-i)

simplify

\frac{6 + 7 i}{8 - i}

\frac{41}{65} + \frac{62}{65} i

Solution steps

\frac{6 + 7 i}{8 - i}

Multiply by the conjugate

\frac{8 + i}{8 + i}

= \frac{( 6 + 7 i ) ( 8 + i )}{( 8 - i ) ( 8 + i )}

Simplify

\frac{( 6 + 7 i ) ( 8 + i )}{( 8 - i ) ( 8 + i )} : \frac{41 + 62 i}{65}

= \frac{41 + 62 i}{65}

Rewrite in standard complex form:

\frac{41}{65} + \frac{62}{65} i

= \frac{41}{65} + \frac{62}{65} i

(2.001)^{5}

\frac{\frac{x - 10}{35 x + 21}}{\frac{7}{35 x + 21}}

\frac{x ^{2} - 4 x}{x ^{2} - 16}

(16 x^{4})^{\frac{3}{4}}

1.3 \cdot 1 0^{6} - 6.8 \cdot 1 0^{5}