What is (4x+8)/(x^2-4)*(x^2+x-6)/(x^2+3x) ?

The solution to (4x+8)/(x^2-4)*(x^2+x-6)/(x^2+3x) is 4/x

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simplify (4x+8)/(x^2-4)*(x^2+x-6)/(x^2+3x)

simplify

\frac{4 x + 8}{x ^{2} - 4} \cdot \frac{x ^{2} + x - 6}{x ^{2} + 3 x}

\frac{4}{x}

Solution steps

\frac{4 x + 8}{x ^{2} - 4} \cdot \frac{x ^{2} + x - 6}{x ^{2} + 3 x}

Cancel

\frac{4 x + 8}{x ^{2} - 4} : \frac{4}{x - 2}

= \frac{4}{x - 2} \cdot \frac{x ^{2} + x - 6}{x ^{2} + 3 x}

Cancel

\frac{x ^{2} + x - 6}{x ^{2} + 3 x} : \frac{x - 2}{x}

= \frac{4}{x - 2} \cdot \frac{x - 2}{x}

Cross-cancel common factor:

x - 2

= \frac{4}{x}

\frac{1 + - 64}{2 - 8 i}

(1.25)^{2}

5 + (- 3) (6 x - 5)

5^{2} + 1 0^{2}

(x - 3) (y + 2)

What is (4x+8)/(x^2-4)*(x^2+x-6)/(x^2+3x) ?
The solution to (4x+8)/(x^2-4)*(x^2+x-6)/(x^2+3x) is 4/x