What is log_{4}(13.928) ?

The solution to log_{4}(13.928) is log_{4}(1741)-3log_{4}(5)

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simplify log_{4}(13.928)

simplify

lo g_{4} (13.928)

lo g_{4} (1741) - 3 lo g_{4} (5)

Decimal Notation

1.89995 \dots

Solution steps

lo g_{4} (13.928)

13.928 = \frac{13928}{1000}

= lo g_{4} (\frac{13928}{1000})

Cancel

\frac{13928}{1000} : \frac{1741}{125}

= lo g_{4} (\frac{1741}{125})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{4} (\frac{1741}{125}) = lo g_{4} (1741) - lo g_{4} (125)

= lo g_{4} (1741) - lo g_{4} (125)

lo g_{4} (125) = 3 lo g_{4} (5)

= lo g_{4} (1741) - 3 lo g_{4} (5)

3^{5} \cdot 3^{4}

cos^{2} (θ) - 1

1 - cos^{2} (2 x)

\frac{3 b ^{2} + 13 b + 4}{b + 4}

\frac{3 x ^{2} + 9 x ^{3} - 12 x ^{4}}{- 3 x ^{2}}

What is log_{4}(13.928) ?
The solution to log_{4}(13.928) is log_{4}(1741)-3log_{4}(5)