What is i^3(i^2+i^5) ?

The solution to i^3(i^2+i^5) is 1+i

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simplify i^3(i^2+i^5)

simplify

i^{3} (i^{2} + i^{5})

1 + i

Solution steps

i^{3} (i^{2} + i^{5})

Apply the distributive law:

a (b + c) = ab + a c

i^{3} (i^{2} + i^{5}) = i^{3} i^{2} + i^{3} i^{5}

= i^{3} i^{2} + i^{3} i^{5}

i^{3} i^{2} = i

i^{3} i^{5} = 1

= i + 1

Rewrite in standard complex form:

1 + i

= 1 + i

5 - 4 x - x^{2}

\frac{15 ( x ^{- 2} ) ^{3}}{3 ( x ^{- 4} ) ^{- 3}}

20 t^{9}

2^{16}