What is (3-2i)/(2+i)-(1+i)/(1-i) ?

The solution to (3-2i)/(2+i)-(1+i)/(1-i) is 4/5-12/5 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3-2i)/(2+i)-(1+i)/(1-i)

simplify

\frac{3 - 2 i}{2 + i} - \frac{1 + i}{1 - i}

\frac{4}{5} - \frac{12}{5} i

Solution steps

\frac{3 - 2 i}{2 + i} - \frac{1 + i}{1 - i}

\frac{3 - 2 i}{2 + i} = \frac{4 - 7 i}{5}

\frac{1 + i}{1 - i} = i

= \frac{4 - 7 i}{5} - i

Join

\frac{4 - 7 i}{5} - i : \frac{- 12 i + 4}{5}

= \frac{- 12 i + 4}{5}

Rewrite in standard complex form:

\frac{4}{5} - \frac{12}{5} i

= \frac{4}{5} - \frac{12}{5} i

(- 7 x^{5}) (9 x^{5})

(v - 5) (v + 3) (v + 2)

2 cos (x) \cdot (- sin (x))

\frac{7}{x - 3} + \frac{3}{x + 5}

lo g_{2} (x - 1) - 3 lo g_{2} (x) - 2 lo g_{2} (x + 1)

What is (3-2i)/(2+i)-(1+i)/(1-i) ?
The solution to (3-2i)/(2+i)-(1+i)/(1-i) is 4/5-12/5 i