What is 1/3 (3x^2+9)^2-9 ?

The solution to 1/3 (3x^2+9)^2-9 is 3x^4+18x^2+18

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simplify 1/3 (3x^2+9)^2-9

simplify

\frac{1}{3} (3 x^{2} + 9)^{2} - 9

3 x^{4} + 18 x^{2} + 18

Solution steps

\frac{1}{3} (3 x^{2} + 9)^{2} - 9

Expand

\frac{1}{3} (3 x^{2} + 9)^{2} : 3 x^{4} + 18 x^{2} + 27

= 3 x^{4} + 18 x^{2} + 27 - 9

Subtract the numbers:

27 - 9 = 18

= 3 x^{4} + 18 x^{2} + 18

\frac{3}{x} \cdot \frac{x - 1}{6}

\frac{x}{2}

\frac{2 x ^{2} - 12 x}{x ^{2} - 3 x - 18}

\frac{3}{8} \times \frac{5}{6} \div \frac{1}{4}

\frac{1}{2} + 2