What is (\frac{n-15)/(9n)}{(15-n)/(3n^5)} ?

The solution to (\frac{n-15)/(9n)}{(15-n)/(3n^5)} is -(n^4)/3

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simplify (\frac{n-15)/(9n)}{(15-n)/(3n^5)}

simplify

\frac{\frac{n - 15}{9 n}}{\frac{15 - n}{3 n ^{5}}}

- \frac{n ^{4}}{3}

Solution steps

\frac{\frac{n - 15}{9 n}}{\frac{15 - n}{3 n ^{5}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( n - 15 ) \cdot 3 n ^{5}}{9 n ( 15 - n )}

Cancel

\frac{( n - 15 ) \cdot 3 n ^{5}}{9 n ( 15 - n )} : - \frac{n ^{4}}{3}

= - \frac{n ^{4}}{3}

10 \cdot 9

\frac{1}{2} \frac{1}{2}

5 (\frac{x + 8}{5} - 8)

(x + 7) (x - 9)

What is (\frac{n-15)/(9n)}{(15-n)/(3n^5)} ?
The solution to (\frac{n-15)/(9n)}{(15-n)/(3n^5)} is -(n^4)/3