What is factor 8x^2+10xy+3y^2 ?

The solution to factor 8x^2+10xy+3y^2 is (2x+y)(4x+3y)

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factor 8x^2+10xy+3y^2

factor

8 x^{2} + 10 x y + 3 y^{2}

(2 x + y) (4 x + 3 y)

Solution steps

8 x^{2} + 10 x y + 3 y^{2}

Break the expression into groups

= (8 x^{2} + 4 x y) + (6 x y + 3 y^{2})

Factor out

4 x

from

8 x^{2} + 4 x y : 4 x (2 x + y)

Factor out

3 y

from

6 x y + 3 y^{2} : 3 y (2 x + y)

= 4 x (2 x + y) + 3 y (2 x + y)

Factor out common term

2 x + y

= (2 x + y) (4 x + 3 y)

(x^{2} + 3 x - 10) \frac{6}{3 x - 6}

\frac{x - 5}{4 x + 8} \cdot (12 x^{2} + 32 x + 16)

x (2 x^{2} + 3 x y + y^{2}) - y (5 x^{2} - 2 x y + y^{2})

(7 - 5) (7 + 5)

cot^{2} (x) - cot^{2} (x) cos^{2} (x)

What is factor 8x^2+10xy+3y^2 ?
The solution to factor 8x^2+10xy+3y^2 is (2x+y)(4x+3y)