What is (2^4)/((-4)+sqrt(25*4)+(3*3-5)^2) ?

The solution to (2^4)/((-4)+sqrt(25*4)+(3*3-5)^2) is 8/11

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simplify (2^4)/((-4)+sqrt(254)+(33-5)^2)

simplify

\frac{2 ^{4}}{( - 4 ) + 25 \cdot 4 + ( 3 \cdot 3 - 5 ) ^{2}}

\frac{8}{11}

Decimal Notation

0.72727 \dots

Solution steps

\frac{2 ^{4}}{( - 4 ) + 25 \cdot 4 + ( 3 \cdot 3 - 5 ) ^{2}}

Apply rule:

(- a) = - a

(- 4) = - 4

= \frac{2 ^{4}}{- 4 + 25 \cdot 4 + ( 3 \cdot 3 - 5 ) ^{2}}

- 4 + 25 \cdot 4 + (3 \cdot 3 - 5)^{2} = 22

= \frac{2 ^{4}}{22}

Factor the number:

22 = 2 \cdot 11

= \frac{2 ^{4}}{2 \cdot 11}

\frac{2 ^{4}}{2} = 2^{3}

= \frac{2 ^{3}}{11}

2^{3} = 8

= \frac{8}{11}

(3 + 4 i) + (5 - 2 i)

(- 5) (i)

\frac{( tan ( x ) + cot ( x ) )}{sec ( x )}

5 x^{8} - 5 x^{6}

\frac{\frac{8 x}{3 x}}{\frac{4}{7}}

What is (2^4)/((-4)+sqrt(25*4)+(3*3-5)^2) ?
The solution to (2^4)/((-4)+sqrt(25*4)+(3*3-5)^2) is 8/11