What is the answer to (3x-7}{12}-\frac{2x-3)/6 =(x-1)/8 ?

The answer to (3x-7}{12}-\frac{2x-3)/6 =(x-1)/8 is x= 1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3x-7}{12}-\frac{2x-3)/6 =(x-1)/8

\frac{3 x - 7}{12} - \frac{2 x - 3}{6} = \frac{x - 1}{8}

x = \frac{1}{5}

Decimal

x = 0.2

Solution steps

\frac{3 x - 7}{12} - \frac{2 x - 3}{6} = \frac{x - 1}{8}

Multiply by LCM

2 (3 x - 7) - 4 (2 x - 3) = 3 (x - 1)

Expand

2 (3 x - 7) - 4 (2 x - 3) : - 2 x - 2

Expand

3 (x - 1) : 3 x - 3

- 2 x - 2 = 3 x - 3

Move

2

to the right side

- 2 x = 3 x - 1

Move

3 x

to the left side

- 5 x = - 1

Divide both sides by

- 5

x = \frac{1}{5}

(3 - 5)^{2}

\frac{c}{3} = \frac{30}{5}

x^{2} = 3 x^{2} - 75

\frac{4 i}{7 - 4 i}

1 - \frac{9}{49}

What is the answer to (3x-7}{12}-\frac{2x-3)/6 =(x-1)/8 ?
The answer to (3x-7}{12}-\frac{2x-3)/6 =(x-1)/8 is x= 1/5
Solve for x: (3x-7}{12}-\frac{2x-3)/6 =(x-1)/8
The solution is x= 1/5