What is ((b^8*(a^3)^4)/(2*b^4*a^6))^3 ?

The solution to ((b^8*(a^3)^4)/(2*b^4*a^6))^3 is (b^{12}a^{18})/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((b^8(a^3)^4)/(2b^4*a^6))^3

simplify

(\frac{b ^{8} \cdot ( a ^{3} ) ^{4}}{2 \cdot b ^{4} \cdot a ^{6}})^{3}

\frac{b ^{12} a ^{18}}{8}

Solution steps

(\frac{b ^{8} ( a ^{3} ) ^{4}}{2 b ^{4} a ^{6}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( b ^{8} ( a ^{3} ) ^{4} ) ^{3}}{( 2 b ^{4} a ^{6} ) ^{3}}

Simplify

(b^{8} (a^{3})^{4})^{3} : b^{24} a^{36}

= \frac{b ^{24} a ^{36}}{( 2 b ^{4} a ^{6} ) ^{3}}

Simplify

(2 b^{4} a^{6})^{3} : 8 b^{12} a^{18}

= \frac{b ^{24} a ^{36}}{8 b ^{12} a ^{18}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{b ^{24}}{b ^{12}} = b^{24 - 12}

= \frac{a ^{36} b ^{24 - 12}}{8 a ^{18}}

Subtract the numbers:

24 - 12 = 12

= \frac{b ^{12} a ^{36}}{8 a ^{18}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{a ^{36}}{a ^{18}} = a^{36 - 18}

= \frac{b ^{12} a ^{36 - 18}}{8}

Subtract the numbers:

36 - 18 = 18

= \frac{b ^{12} a ^{18}}{8}

(x^{3} - 2)^{2}

2 + 2 cos (θ)

(2 x + 3)^{2} - (2 x + 1)^{2} - 2^{3}

4 \cdot 28

\frac{( x + 3 y ) ^{2} - 3 y ( 2 x - 3 y ) - 18 y ^{2}}{2 x ^{2}}

What is ((b^8*(a^3)^4)/(2*b^4*a^6))^3 ?
The solution to ((b^8*(a^3)^4)/(2*b^4*a^6))^3 is (b^{12}a^{18})/8